Given:
Since AB and PQ are parallel and AQ is transversal:
- ∠BAQ ≅ ∠PQA as alternate interior angles.
Since AB and PQ are parallel and BP is transversal:
- ∠ABP ≅ ∠QPB as alternate interior angles.
This gives us:
- ΔABO ≅ ΔQPO as per ASA (angle-side-angle)
Since the triangles are congruent, their corresponding sides are congruent too: