197k views
3 votes
A = 8, b = 4, and c = 16

A = 8, b = 4, and c = 16-example-1
User Euan Smith
by
8.7k points

2 Answers

6 votes

Answer:


3 (4)/(31)

Explanation:


\frac{2(4) + 3(16) {}^(2) }{4(8) {}^(2) - 2(4) }


(776)/(248)


3 (4)/(31)

User CRDave
by
8.5k points
3 votes

Answer:
\sf 3(4)/(31) \quad or \quad (97)/(31)

-------------------------------------------------------------------------------------------------------

The given expression:


\sf (2b + 3c^2)/(4a^2 - 2b)

Here given a = 8, b = 4, and c = 16

Inserting this values


\sf (2(4) + 3(16)^2)/(4(8)^2 - 2(4))

Simplify following


\sf (8 + 3(256))/(4(64) - 8)

Distribute inside parenthesis


\sf (8 + 768)/(256 - 8)

Add/Subtract similar terms


\sf (776)/(248)

Simplify following, in improper fraction


\sf (97)/(31)

In mixed fraction, answer:


\sf 3(4)/(31)

User RJ Adriaansen
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories