Answer:
a = (vf^2-vi^2)/2s
Step-by-step explanation:
vf^2=vi^2+2as, where vi is the initial velocity and vf is the final velocity (in m/sec), and s is distance, in meters. [Note that this expression assumes constant acceleration].
To solve for a, rearrange:
vf^2=vi^2+2as
vf^2-vi^2 = 2as
2as = vf^2-vi^2
a = (vf^2-vi^2)/2s