Question

How much tension must a cable withstand if it is used to accelerate a 1200-kg car vertically upwards at 0.7 m/s^2

Answer 1

M a = T - M g acceleration of car where T is tension in cable

T = M (g + a) = M (9.80 + .7) = M * 10.5

T = 1200 * 10.5 = 12,600 N