Question

I will give braniest to the person that answers all of the given questions

A bee flies at 20 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for 11 ​minutes, and then flies directly back to the hive at 16 feet per second. It is away from the hive for a total of 13 minutes.

a. What equation can you use to find the distance of the flowerbed from the​ hive?

b. How far is the flowerbed from the hive?

a. Write the equation. Let d be the distance of the flowerbed from the hive

Answer 1

Below in bold.

Explanation:

a. Distance = speed * time

d = st

So substituting in the given values:

d = 20t where t is the time it takes to travel from the hive to the flowerbed.

The total time that the bee is inflight = 13-11 = 2 minutes

= 120 seconds.

So for the return flight the time taken is (120-t) seconds.

So d = 16(120 - t).

and we can find the distance from the hive to flowerbed by solving the the 2 equations highlighted.

b, d = 20t

d = 16(120 - t).

As both right side expressions are equal to d we can write:

20t = 16(120 - t)

20t = 1920 - 16t

20t+ 16t = 1920

t = 1920/36

= 53.33 seconds.

So the distance from hive to flowerbed

= 53.33 * 20

= 1066.67 feet.