Question

I already know the answer to this problem, I want a explanation on how to get the answer.

Answer 1

`\\ \bull\tt\dashrightarrow BC=CE`

`\\ \bull\tt\dashrightarrow 3x+3y=7x+5y`

`\\ \bull\tt\dashrightarrow 7x-3x=3y-5y`

`\\ \bull\tt\dashrightarrow 4x=-2y`

`\\ \bull\tt\dashrightarrow 2x=-y`

`\\ \bull\tt\dashrightarrow (x)/(y)=(-1)/(2)`

Now

`\\ \bull\tt\dashrightarrow BE=BC+CE+CD`

`\\ \bull\tt\dashrightarrow BE=3x+3y+7x+5y+5x-2y+6`

`\\ \bull\tt\dashrightarrow BE=15x+6y+6`

Answer 2

• BC = CD

`(3x + 3y) = (5x - 2y + 6) \\ 5x - 3x = - 2y - 3y + 6 \\ 2x = - 5y + 6 \\ \\ \dashrightarrow \: { \tt{x = ( - 5y + 6)/(2) }}`

• find BE:

`\dashrightarrow \: { \tt{BE = (3x + 3y) + (7x + 5y)}} \\ \\{ \tt{BE = 10x + 8y}}`