Question

A ball is launched from the ground with a horizontal speed of 30 m/s and a vertical speed of 30 m/s. How far horizontally will it travel in 2 seconds?

Answer 1

Step-by-step explanation:

You can use a one-dimensional physics equation to find the horizontal distance:

Δx =
`v_(0)t+(1)/(2)at^2` where v0 is the initial velocity (30 m/s), t is time, and a is accleration. There is 0 acceleration in the horizontal dimension so the equation becomes

Δx
`=v_(0)t` which is a fancy and meant-to-be-intimidating version of "distance - rate times time". The delta x is the distance traveled and our known, v0 is the initial velocity, and t is time. We have the rate and the time:

Δx =
`(30)2_` which gives us the horizontal distance of 60 meters