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Through (-4,5) and parallel to y = -3/2x-5

User Gedweb
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1 Answer

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**Disclaimer** Hi there! I assumed the question to be asking for a line expression. The following answer will be according to this understanding. Please let me know if I am incorrect and I will modify my answer correspondingly

Answer:
\Large\boxed{y-5=-(3)/(2) (x+4)}

Explanation:

Given information


\text{Pass~through~point}=(x_1,~y_1)=(-4,~5)


\text{Parallel~to}:y=-(3)/(2) x-5

Given equation form

Point-slope form is the most efficient way to write the expression


\text{Point-slope form}:y-y_1=m(x-x_1)


(x_1,~y_1)=\text{A point that the line passes through}


m=\text{Slope}

Determine the slope


\text{Since the line is parallel to } y=-(3)/(2) x-5 \text{ , by the property of parallel}\\\text{lines, the slope of the given line is also }-(3)/(2)


\text{Therefore, m}=-(3)/(2)

Substitute values into the given form


y-y_1=m(x-x_1)


y-(5)=-(3)/(2) (x-(-4)

Simplify the expression


\Large\boxed{y-5=-(3)/(2) (x+4)}

Hope this helps!! :)

Please let me know if you have any questions

User TomCB
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