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45 votes
45 votes
Find an equation of the line with the given properties parallel to y=-1/3x-2 containing the pt (6,-10)

User WhiZTiM
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1 Answer

11 votes
11 votes

Answer:

y + 10 = -1/3 (x - 6) OR y = -1/3x-8

Explanation:

take the slope of y = -1/3x - 2 (the slope is -1/3)

plug the slope and the point into this equation: y - y1 = m (x - x1)

m represents your slope, y1 and x1 represnt your points so just plug in

so y + 10 = -1/3 (x - 6) or y = -1/3x-8 (subtract 10 from both sides and distribute the -1/3 to (x -6)).

User Sunil Sapkota
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3.2k points