Question

RS=2x-8, ST = 11, RT = x+10

Answer 1

`Equation~=~\Large\boxed{2x+3=x+10}`

`x~=~\Large\boxed{7}`

`RS~=~\Large\boxed{6}`

`RT~=~\Large\boxed{17}`

Explanation:

Given information

`RS=2x-8`

`ST=11`

`RT=x+10`

Derived expression from the given information

Presumably, I think this is a combination of segments

`RS+ST=RT`

Substitute values into the given expression

`(2x-8)+(11)=(x+10)`

Combine like terms

The following is the expression

`\Large\boxed{2x+3=x+10}`

Subtract 3 on both sides

`2x+3-3=x+10-3`

`2x=x+7`

Subtract x on both sides

`2x-x=x+7-x`

`\Large\boxed{x=7}`

Substitute the x value into corresponding expressions to determine the final value

`RS=2x-8=2(7)-8=14-8=\Large\boxed{6}`

`RT=x+10=(7)+10=\Large\boxed{17}`

Hope this helps!! :)

Please let me know if you have any questions