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RS=2x-8, ST = 11, RT = x+10

RS=2x-8, ST = 11, RT = x+10-example-1

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2 votes

Answer:


Equation~=~\Large\boxed{2x+3=x+10}


x~=~\Large\boxed{7}


RS~=~\Large\boxed{6}


RT~=~\Large\boxed{17}

Explanation:

Given information


RS=2x-8


ST=11


RT=x+10

Derived expression from the given information

Presumably, I think this is a combination of segments


RS+ST=RT

Substitute values into the given expression


(2x-8)+(11)=(x+10)

Combine like terms

The following is the expression


\Large\boxed{2x+3=x+10}

Subtract 3 on both sides


2x+3-3=x+10-3


2x=x+7

Subtract x on both sides


2x-x=x+7-x


\Large\boxed{x=7}

Substitute the x value into corresponding expressions to determine the final value


RS=2x-8=2(7)-8=14-8=\Large\boxed{6}


RT=x+10=(7)+10=\Large\boxed{17}

Hope this helps!! :)

Please let me know if you have any questions

User Taruni
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