Question

A 74.0-gram piece of metal at 94.0 °C is placed in 120.0 g of water in a calorimeter at 26.5 °C. The final temperature in the calorimeter is 32.0 °C. Determine the specific heat of the metal. Show your work by listing various steps, and explain how the law of conservation of energy applies to this situation.

Answer 1

Let's begin

`\\ \rm\Rrightarrow m_1c\Delta T_1=m_2c\Delta T`

• Remember c won't be cancelled ,2nd c is for water

• ∆T =32-26.5=5.5°C
• c for water 1kcal

`\\ \rm\Rrightarrow 0.074(94)c=((74+120)(1)(5.5))/(1000)`

`\\ \rm\Rrightarrow 6.956c=((194)(5.5))/(1000)`

`\\ \rm\Rrightarrow 6.956c=1.067`

`\\ \rm\Rrightarrow c=0.00015kcal/kg°C`

`\\ \rm\Rrightarrow c=0.015cal/g°C`