Question

Pleaseee helpppp <3

What is the following solution of h=-16t^2 +36t + 4

Thank you all so much!

Answer 1

`h=-16t^2+36t+4\implies \stackrel{h}{0}=4(-4t^2+9t+1)\implies 0=-4t^2+9t+1 \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{quadratic formula} \\\\ 0=\stackrel{\stackrel{a}{\downarrow }}{-4}t^2\stackrel{\stackrel{b}{\downarrow }}{+9}t\stackrel{\stackrel{c}{\downarrow }}{+1} \qquad \qquad t= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}`

`t= \cfrac{ - (9) \pm \sqrt { (9)^2 -4(-4)(1)}}{2(-4)} \implies t = \cfrac{ -9 \pm \sqrt { 81 +16}}{ -8 } \\\\\\ t= \cfrac{ -9 \pm \sqrt { 97 }}{ -8 }\implies t=\cfrac{9\mp√(97)}{8}`