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Hi good evening, I have been having some trouble with these equations, if you don't mind it would be nice if you helped me get the correct answer. Thank u in advance :)))))

1) y=-x+2
2) y=2/3x-1


*Keep in mind these are going to be graphed, they
are known as Graphed Linear Equations.

Hi good evening, I have been having some trouble with these equations, if you don-example-1

1 Answer

2 votes

Check the picture below.

to graph a LINEar equation, since it's just a line and for a line all you need is two points and draw away, simply pick two random "x" values to get the "y" values and plot those two points.

for y = -x + 2

if we choose x = 0, then y = -0 + 2 => y = 2, that gives us the point (0 , 2)

if we choose x = 2, then y = -2 + 2 => y = 0, that gives us the point (2 , 0)

graph it and we get the blue line.

for the 2nd equation


y = \cfrac{2}{3}x-1\hspace{5em}\underline{x=3}~\hfill y=\cfrac{2}{3}(3)-1\implies y=2-1\implies y=1 \\\\\\ ~\hfill \boxed{(3~~,~~1)} \\\\\\ ~\hspace{9.5em}\underline{x=0}~\hfill y=\cfrac{2}{3}(0)-1\implies y=-1 \\\\\\ ~\hfill \boxed{(0~~,~~-1)}

graph it and we get the red line

notice, those points are in those lines, and to graph a LINE, all you need is two points.

Hi good evening, I have been having some trouble with these equations, if you don-example-1
User Efe
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