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Passes through (-6,2) and is parallel to the line whose equation is 2x-3y=12

1 Answer

4 votes


Answer:\large\boxed{y=(2)/(3) x+6}

Explanation:

First let's convert 2x - 3y = 12 into
y = mx + b form.

In order to do this, solve for y.


2x-3y=12


-3y=-2x+12


y=(2)/(3) x-4

This shows us that the slope is
\boxed{(2)/(3)}


Now we use the point-slope formula:


(y-y1)=m(x-x1)

where m is the slope and y1 and x1 are the point the line passes through

Using the point (-6,2) and slope, 2/3, we can find the equation:


(y-2)=(2)/(3) (x-(-6))


(y-2)=(2)/(3) (x+6)


(y-2)=(2)/(3) x+4


\large\boxed{y=(2)/(3) x+6}

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