Question

An aluminum block of mass 12.00 kg is heated from 20 c to 118 c. if the specific heat of aluminum is 913 j-1 kg k-1 then how much energy is required?

Answer 1

107 kJ

Step-by-step explanation:

12.00 kg * 913 J /kg-C * (118-20)°C ( I corrected spec heat units)

( a C degree change is the same as a kelvin change)

= 1 073 688 J = 107 kJ ( three sig digits)