![\displaystyle\\Answer:P(A)=(1)/(6).](https://img.qammunity.org/2023/formulas/mathematics/high-school/lusn2mevtjxc0nnlvoujuhsiipkbth94cu.png)
Explanation:
If one of the dice has a 6, then the other dice should have a 1 (7-6=1).
A dice has six faces and each face has a different number from 1 to 6.
Consequently, the probability that on a dice the digit 1 will fall is equal:
![\displaystyle\\P(A)=(1)/(6).](https://img.qammunity.org/2023/formulas/mathematics/high-school/used2vr7mpe2cankbjku9ahacr28fzzipj.png)
This is the solution to the problem.