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What is the oxidation number of boron in Na(B(NO3)4)
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What is the oxidation number of boron in Na(B(NO3)4)

User Nick Kitto
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1 Answer

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Answer:

+3

Step-by-step explanation:

oxidation state of hydrogen in NaBH4 is -1 because here hydrogen acts as hydride. thus the oxidation state od boron in sodium boron hydride is (+3)

User Shannon Matthews
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