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What is the midline equation of y = -4sin (2x - 7) + 3?

User Lipka
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2 Answers

1 vote

Answer:


y = 3.

Explanation:

The minimum and maximum value of
\sin(2\, x - 7) over all real
x are
(-1) and
1, respectively. Hence, the maximum and minimum value of
y = -4\, \sin(2\, x - 7) + 3 would be:

  • Maximum:
    y = (-4)\, (-1) + 3 = 7.
  • Minimum:
    y = (-4)\, (1)\ + 3 = (-1).

The midline equation of a sine wave is a horizontal line that is right in the middle of maximum and minimum
y-values of that sine wave. In the sine wave in this question, the average of the maximum and minimum
y\!-values is
(1/2) \, (7 + (-1)) = 3. Hence, the midline equation of this sine wave would be
y = 3.

User Tborzecki
by
3.4k points
4 votes


\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}

Given:


\longrightarrow \sf{y = -4 \sin (2x - 7) + 3}

This is the equation of the horizontal line equal to the average value of y for the function given.


\leadsto This will correspond to the value where the sine function has a value of 0, which is the average value of the function:


\longrightarrow \sf{Y_(avg ) = −4(0) + 3 = 0 + 3 = 3}


\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}


\small\bm{The \: equation\: of \: the \: midline \: is \: \: y=3.}

What is the midline equation of y = -4sin (2x - 7) + 3?-example-1
User Danielfeelfine
by
4.5k points