Question

Someone help me please

Answer 1

• First term=a=15
• Common difference=d=3

`\\ \bull\tt\dashrightarrow a_n=a+(n-1)d`

`\\ \bull\tt\dashrightarrow a_(10)=a+9d`

`\\ \bull\tt\dashrightarrow a_(10)=10+9(3)`

`\\ \bull\tt\dashrightarrow a_(10)=15+27`

`\\ \bull\tt\dashrightarrow a_(10)=42`

Answer 2

• 42 seats

Explanation:

This represents an arithmetic progression with the first term of a = 15 and common difference of d = 3.

The tenth row is the 10th term:

• aₙ = a + (n - 1)d

The row 10 has:

• a₁₀ = 15 + 9*3 = 15 + 27 = 42 seats