Answer:
8.64 L
Step-by-step explanation:
If 0.29 moles of Ar occupies 3.8L at a specified P and T, then 0.66 moles would occupy:
(0.66 moles/0.29 moles)*(3.8L) = 8.64 L
As long as the pressure and temperature do not change, the volume will scale proportionately to the change in moles.