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28 votes
28 votes
If anyone can help me??

If anyone can help me??-example-1
User DePatinkin
by
2.2k points

2 Answers

24 votes
24 votes

Answer:

f(x) = 4

Step-by-step explanation:

Firstly circle upon the graph where the f(x) = y is being where the curve crosses y

At y = -2

This must mean where -2 is y then we see that x = 0 as its the y axis.

The f (-2) therefore means 0 moves to -2 which makes the y axis = 4

as this crosses at 4

The parabola simply transitions right when we are given a negative f value being our y value and wherever it crosses y we can always relate to x staying at 0 to define our table well at least the starting point of a x^2 curve table.

To find already plotted graph gradient to check where x = 0

The slope can be measured becomes the tangent line on left side inside on same line can be measured at rise 7 run 1.5 = 7 / 3/2 = 4.66666667 approx = 4.67 gradient.

When f(x) = 4 = y

Then we can multiply 7/3/2 into the equation

y = x^2 -2x + 4

and here we found the equation.

User Aleks
by
2.8k points
21 votes
21 votes

Answer:


f(-2) = \underline{4}

Step-by-step explanation:

Assuming we don't know how
f(x) is defined but we are given by its graph, We can see that the point
(-2, 4) is on the graph of
f(x). Therefore,
f(-2) = 4.

User Dayong
by
2.6k points
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