Question

We toss a fair coin 4 times. Let X count heads. Find P(X = 0) to nearest ten thousandth (4 decimal places).

Answer 1

P (x = 0) 1/16 = 0.0625

Explanation:

We toss a fair coin 4 times.

HT HT HT HT 4/4 of each if TH TH TH TH etc..

HT HT HT TH 3/4

HT HT TH HT 3/4

HT HT TH TH 1/2

Let X count heads. Find P(X = 0) to nearest ten thousandth (4 decimal places).

P (x = 0) 1/16 = 0.0625

We cna find the average by multiplying a midpoint on one half findings on one side ie) 4/4 x 3/4 x 3/4 x 1/2 = 0.2813

Answer 2

Explanation:

If you toss the coin 4 times, you get 2 * 2 * 2 * 2 possible outcomes, which is 16 outcomes.

There is only 1 outcome where P(x = 0) is possible and that would be

T T T T

one out of 16 is .0625. So

Answer: P(x = 0 ) = 0.0625