Question

2 (a) A plane from airport A flies 280 km to the east to airport B. The plane then travelled north to airport C, 190 km away. (i) Sketch the displacement of the plane. (ii) Determine the resultant displacement. [5 marks] [ANS: DIY, DIY, 338 km, 34.16° from north of east]​

Answer 1

See below

Step-by-step explanation:

280 km east then 190 km north

Use Pythagorean theorem to find the resultant displacement

d^2 = 280^2 + 190^2

d = 338.4 km

Angle will be arctan ( 190/280) = 34.16 °