Question

What is an equation of the line that passes through the points (-6,-5) and
(-2, 3)

Answer 1

`y=-0.500x+2`

Explanation:

Given the following question:

point A = (-6, 5)
point B = (-2, 3)

To find the equation of the line we have to find the slope intercept, where m is the slope of the given line.

Formula for slope intercept:


`y=mx+b`

First, we need to fine the slope of the given points because m is the slope.


`m=(y2-y1)/(x2-x1)`

`m=(3-5)/(2--6) =(-2)/(4) =-0.500`

`m=-0.500`


`y=mx+b`

`y=5`

`m=-0.500`

`x=-6`

`5=-0.500(-6)+b`

`-0.500*-6=3`

`5=3+b`

`5-3=2`

`2+b`

`b=2`


`y=-0.500x+2`

Hope this helps.