Question

O:250 degrees
A
In this figure, mzBDA =
• and m2BCA =
Please

Answer 1

∠ BDA = 55° , ∠ BCA = 70°

Explanation:

∠ BOA = 360° - 250° = 110° ( angles round a point )

The central angle is twice the angle on the circle, subtended on the same arc

∠ BDA =
`(1)/(2)` ∠ BOA =
`(1)/(2)` × 110° = 55°

OBCA is a tangent kite

Opposite angles sum to 180° , then

∠ BCA = 180° - ∠ BOA = 180° - 110° = 70°