Question

Help pls i dont understand how to do this :')

Answer 1

7/8

Explanation:

Use the Pythagorean Identity

`( \sin(x) ) {}^(2) + ( \cos(x) ) {}^(2) = 1`

Plug in

`( √(15) )/(8)`

for cos x.

`(\sin(x) ) {}^(2) + ( ( √(15) )/(8) ) {}^(2) = 1`

`( \sin(x) ) {}^(2) + (15)/(64) = 1`

`( \sin(x) ) {}^(2) = (49)/(64)`

`\sin(x) = (7)/(8)`