Answer:
Explanation:
The diagonals of a rhombus are perpendicular to and bisect each other.
The diagonals divide the rhombus into four equal right triangles, with legs equal to half-diagonals and each side of a rhombus is a hypotenuse of the formed triangles.
Let the diagonals be x and y and sides be s.
According to Pythagorean we have:
Given:
Find y:
- (12/2)² + (y/2)² = 10²
- y²/4 = 100 - 36
- y² = 64*4
- y = 16 cm
Area of the rhombus:
- A = xy/2
- A = 12*16/2 = 96 cm²