Answer:
1.) aqueous lithium sulfate + aqueous calcium iodide ---> aqueous lithium iodide + solid calcium sulfate
2.) Li₂SO₄ (aq) + CaI₂ (aq) ------> 2 LiI (aq) + CaSO₄ (s)
Step-by-step explanation:
This appears to be a double-displacement reaction. In these reactions, the cation of one compound swaps with the cation of another.
Therefore, lithium swaps with calcium. The new products are lithium iodide (LiI) and calcium sulfate (CaSO₄). Lithium iodide is soluble in water, whereas calcium sulfate is generally not.
The word equation (including the states of matter):
aqueous lithium sulfate + aqueous calcium iodide ---> aqueous lithium iodide + solid calcium sulfate
An equation is balanced when there is an equal amount of each element on both sides of a reaction. If these amounts are unequal, you can add coefficients to modify the quantities of particular molecules.
The unbalanced equation:
Li₂SO₄ (aq) + CaI₂ (aq) ------> LiI (aq) + CaSO₄ (s)
Reactants: 2 lithium, 1 sulfur, 4 oxygen, 1 calcium, 2 iodine
Products: 1 lithium, 1 sulfur, 4 oxygen, 1 calcium, 1 iodine
The balanced equation:
Li₂SO₄ (aq) + CaI₂ (aq) ------> 2 LiI (aq) + CaSO₄ (s)
Reactants: 2 lithium, 1 sulfur, 4 oxygen, 1 calcium, 2 iodine
Products: 2 lithium, 1 sulfur, 4 oxygen, 1 calcium, 2 iodine