Question

6. Solve the system of equations.

x = 3y + 1
2x+4y= 12
O (10,3)
O (4,1)
(1,4)
(3,10)

Answer 1

(4, 1 )

Explanation:

x = 3y + 1 → (1)

2x + 4y = 12 → (2)

substitute x = 3y + 1 into (2)

2(3y + 1) + 4y = 12

6y + 2 + 4y = 12

10y + 2 = 12 ( subtract 2 from both sides )

10y = 10 ( divide both sides by 10 )

y = 1

substitute y = 1 into (1)

x = 3(1) + 1 = 3 + 1 = 4

solution is (4, 1 )