Question

A rocket initially at rest accelerates at a rate of 60 m/s^2 for 0.58 min. What is it’s speed at the end of this time? Answer in units do m/s

Answer 1

The final speed of the rocket after accelerating at 60 m/s^2 for 0.58 minutes (converting to 34.8 seconds) is 2088 m/s.

Step-by-step explanation:

The question asks us to calculate the final speed of a rocket after it has been accelerating for a certain period of time. Given that the rocket is initially at rest and that it accelerates at a rate of 60 m/s^2 for 0.58 minutes, we can find the final speed using the kinematic equation:

v = vo + at

where v is the final velocity, vo is the initial velocity (which is 0 since the rocket starts from rest), a is the acceleration, and t is the time in seconds.

To use this equation, first convert the time from minutes to seconds:

0.58 min x 60 s/min = 34.8 s

Now, plug in the values into the equation:

v = 0 + (60 m/s^2)(34.8 s)

To find the final velocity:

v = 2088 m/s

So, the rocket's speed at the end of 0.58 minutes is 2088 m/s.

Answer 2

• From first equation of motion:

`{ \boxed{ \bf{v = u + at}}}`

v » final velocity, which is required.

u » initial velocity, u = 0 ( at rest )

a » acceleration, a = 60m/s²

t » time, t = 0.58 mins = 34.8 sec

`v = 0 + (60 * 34.8) \\ v = 2088 \: m {s}^( - 1)`

• Final velocity is 2088 m/s