Answer:
[OH⁻] = 2.2 x 10⁻¹²
Step-by-step explanation:
(Step 1)
Calculate the pH.
pH = -log[H⁺]
pH = -log[4.6 x 10⁻³]
pH = 2.34
(Step 2)
Find the pOH.
pH + pOH = 14
2.34 + pOH = 14
pOH = 11.66
(Step 3)
Calculate the [OH⁻].
[OH⁻] = 10^(-pOH)
[OH-] = 10^(-11.66)
[OH⁻] = 2.2 x 10⁻¹²