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Y = 3x + 15
3x + 3y = 9

User Rmsys
by
7.6k points

1 Answer

5 votes

Answer:


\Large\boxed{x=-3}
\Large\boxed{y=6}

Explanation:

Given the system of equations


1)~y=3x+15


2)~3x+3y=9

Divide 3 on both sides of the 2) equation


3x+3y=9


3x/3+3y/3=9/3


x+y=3

Current system


1)~y=3x+15


2)~x+y=3

Substitute 1) equation into the 2) equation


x+(3x+15)=3

Combine like terms


x+3x+15=3


4x+15=3

Subtract 15 on both sides


4x+15-15=3-15


4x=-12

Divide 4 on both sides


4x/4=-12/4


\Large\boxed{x=-3}

Substitute the x value into one of the equations to find the y value


y=3x+15


y=3(-3)+15


y=-9+15


\Large\boxed{y=6}

Hope this helps!! :)

Please let me know if you have any questions

User Gyfis
by
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