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If the area of the given trapezoid is 1,188m^2, find the value of x.

If the area of the given trapezoid is 1,188m^2, find the value of x.-example-1

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Answer: x = 52 m

Explanation:

The formula we will use, which solves for the area of a trapezoid, is
a=(a+b)/(2) h where a is a base, b is a base, and h is the height.

We will input the known values, then solve for x.


\displaystyle a=(a+b)/(2) h


\displaystyle 1,188\;\text{m}^2=\frac{36\;\text{m}\;+x}{2}*27\;\text{m}


\displaystyle 1,188\;\text{m}^2=(18\;\text{m}+(x)/(2))*27\;\text{m}


\displaystyle 1,188\;\text{m}^2=486\;\text{m}+(27x)/(2)


\displaystyle 702\;\text{m}^2=(27x)/(2)


\displaystyle 1,404\;\text{m}^2=27x


\displaystyle x=52\;\text{m}

User Scott Conway
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