Question

25.0 mL of an LiOH solution were titrated with 29.15 mLof a 0.205 M H3PO4 solution to reach the equivalence point. What is the molarity of the LiOH solution?

Answer 1

0.717 M LiOH

Step-by-step explanation:

(Step 1)

Calculate the moles of H₃PO₄ using the molarity equation.

29.15 mL / 1,000 = 0.02915 L

Molarity = moles / volume (L)

0.205 M = moles / 0.02915 L

0.00598 = moles

(Step 2)

Convert moles H₃PO₄ to moles LiOH using the mole-to-mole ratio from reaction coefficients.

1 H₃PO₄ + 3 LiOH -----> Li₃PO₄ + 3 H₂O
^ ^

0.00598 moles H₃PO₄ 3 moles LiOH
------------------------------------ x -------------------------- = 0.0179 moles LiOH
1 mole H₃PO₄

(Step 3)

Calculate the molarity of LiOH using the molarity equation.

25.0 mL / 1,000 = 0.0250 L

Molarity = moles / volume (L)

Molarity = 0.0179 moles / 0.0250 L

Molarity = 0.717 M