Question

A motor cycle travelling at 10 m/s accelerates at 4m/s for 8s.
what is it final velocity? ​

Answer 1

• Initial velocity=u=10m/s
• Acceleration=a=4m/s^2
• Time=t=8s

Final velocity be v

`\\ \bull\tt\longmapsto v=u+at`

`\\ \bull\tt\longmapsto v=10+4(8)`

`\\ \bull\tt\longmapsto v=10+32`

`\\ \bull\tt\longmapsto v=42m/s`

Answer 2

• From the first newtons equation of motion:

`{ \boxed{ \bf{v = u + at}}}`

v » final velocity which is required.

u » initial velocity, u = 10 m/s

a » acceleration, a = 4 m/s²

t » time, t = 8 seconds

Substitute:

`v = 10 + (4 * 8) \\ v = 10 + 32 \\ v = 42 \: m {s}^( - 1) \\ \\ { \underline{ \underline{ \bf{ \: \: final \: velocity = 42 \: m {s}^( - 1) }}}}`