Question

an angle exceeds three times its complement by 10 find it. please explain properly i will mark as brilliant ​

Answer 1

It's supplementary angle I think

Answer 2

one angle is 20° and the other is 70°

Explanation:

Complementary angles add up to 90°.

Here it is given that an angle exceeds 3 times its complement by 10. So, we are taking the complement as x. Since it exceeds its complement 3 times, we are multiplying the complement 3 times. so we get
`3x`.

Now we also need to add 10, so we get the final equation
`3x+10`, which is the second angle.

As of now, first angle = x and second angle = 3x+10.

Since they are complementary angles, both angles add up to 90°

⇒ 1st angle + 2nd angle = 90°

∴
`x+3x+10 = 90` [since 3x and x are like expressions, we should add 3x + x = 4x]

⇒
`4x = 90 - 10` [by transposing 10 from LHS to RHS]

⇒
`4x = 80`

⇒
`x = (80)/(4)` [by transposing 4 from LHS to RHS]

⇒
`x = 20`

∴The complementary angle is 20° and the given angle is [(3 × 20) + 10)] = 70°