Question

Please help I need you guys

`2x + 12 \leqslant 42`


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Answer 1

My answer is in the photo above

Answer 2

`\displaystyle \large{x \leqslant 15}`

Explanation:

We are given the Inequality:

`\displaystyle \large{2x + 12 \leqslant 42}`

To solve an Inequality, solve it like an equation: We isolate x-term.

First, subtract 12 both sides.

`\displaystyle \large{2x + 12 - 12 \leqslant 42 - 12} \\ \displaystyle \large{2x \leqslant 30}`

Then divide both sides by 2.

`\displaystyle \large{ (2x)/(2) \leqslant (30)/(2) }`

Divide the like term. 2 divides 2 = 1; 2 divides 30 = 15.

`\displaystyle \large{ \frac{ \cancel{2}x}{ \cancel{2}} \leqslant \frac{ \cancel{30}}{ \cancel{2}} } \\ \displaystyle \large{ ( 1x)/( 1) \leqslant (15)/(1) }`

Generally, we do not recommend writing 1 as a denominator as we would just cancel 1 anyways.

That goes the same to 1x which we can simplify to x.

`\displaystyle \large \boxed{ x \leqslant 15}`

Let me know if you have any questions!