Question

pipe A can fill a tank in 3 hours. if pipe B can fill the same tank in 2 hours, how many minutes will it take both pipes to fill 2/3 of the tank​

Answer 1

1. pipe A =3. pipe B=2 find LCM of 3 and 2 . it will be 6 . Then take 6×2/3 it will give you 4 minutes as the answer

Answer 2

48 minutes

Explanation:

The rate of filling from both pipes is the sum of the rates in units of tanks per hour. We want the time for 2/3 of a tank.

Sum of rates

The sum of the filling rates is ...

rate A + rate B = (1/3) tank/hour + (1/2) tank/hour = 5/6 tank/hour

Fill time

The time to fill a tank or part thereof will be the number of tanks divided by the rate in tanks per hour:

time = (2/3 tank)/(5/6 tank/hour) = ((4/6)/(5/6)) hour = 4/5 hour

There are 60 minutes in an hour, so the fill time is ...

(4/5 hour)×(60 min/hour) = 48 min

It will take 48 minutes for both pipes to fill 2/3 of the tank.