Question

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Answer 1

`(3x+6)/(x^2+x-6)`

Explanation:

Notice that we can factor the expression
`x^2-x-2` as
`(x-2)(x+1)`. Similarly, we can express
`3x+3` as
`3(x+1)`. Now, we can multiply the fraction together as
`((x+2)(3)(x+1))/((x-2)(x+1)(x+3)) = (3(x+2))/((x-2)(x+3)) = \boxed{(3x+6)/(x^2+x-6)}`.