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Consider the line 4x + 2y = 8.

What is the slope of a line perpendicular to this line?

2 Answers

5 votes
4x + 2y = 8
y = mx + b
Subtract 4x from both side
2y = 8 - 4x
Divided each term by 2
y = 4 - 2x
y = -2x + 4

Using the slope-intercept form, the slope is -2
m = -2
The equation of a perpendicular line to y = -2x + 4 must has a slope that is the negative reciprocal of the original slope.

M perpendicular = - 1/-2

Move the negative infront of the fraction
M perpendicular = 1/2
User Kambala
by
5.1k points
4 votes

Answer:

supposed to make the subject y then slope is -2

User Palindromer
by
5.4k points
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