Question

Consider the line 4x + 2y = 8.

What is the slope of a line perpendicular to this line?

Answer 1

4x + 2y = 8
y = mx + b
Subtract 4x from both side
2y = 8 - 4x
Divided each term by 2
y = 4 - 2x
y = -2x + 4

Using the slope-intercept form, the slope is -2
m = -2
The equation of a perpendicular line to y = -2x + 4 must has a slope that is the negative reciprocal of the original slope.

M perpendicular = - 1/-2

Move the negative infront of the fraction
M perpendicular = 1/2

Answer 2

supposed to make the subject y then slope is -2