Question

A girl, standing on a bridge, throws a stone vertically downward with an initial velocity of 12.0 m/s, into the river below. if the stone hits the water 2.50 seconds later, what is the height of the bridge above the water?

Answer 1

60.7 m high

Step-by-step explanation:

d = v t + 1/2 a t^2

= 12 (2.5) + 1/2 (9.81)(2.5^2) = 60.7 m