Question

Need help with this plz

Answer 1

Answer: 65

============================================================

Step-by-step explanation:

We'll need to compute the difference quotient. In this case, we need to find what
`(g(h+t)-g(t))/(h)` is equal to. It's called a difference quotient because there's a subtraction in the numerator (aka "difference") and we're dividing to form the quotient.

The idea is that as h approaches 0, then that expression I wrote will approach the derivative we're after. Keep in mind that h will technically never get to 0 itself. It only gets closer and closer.

Anyways, let's compute
`g(h+t)` first

`g(t) = 5t^2+5t\\\\g(h+t) = 5(h+t)^2+5(h+t)\\\\g(h+t) = 5(h^2+2ht+t^2)+5(h+t)\\\\g(h+t) = 5h^2+10ht+5t^2+5h+5t\\\\`

Then we'll subtract off g(t)

`g(h+t)-g(t) = (5h^2+10ht+5t^2+5h+5t) - (5t^2+5t)\\\\g(h+t)-g(t) = 5h^2+10ht+5t^2+5h+5t - 5t^2-5t\\\\g(h+t)-g(t) = 5h^2+10ht+5h\\\\`

A very important thing to notice: the terms that don't have any 'h's in them have been canceled out (eg: 5t^2 combined with -5t^2 added to 0). Why is this important? It's because we need to factor 'h' out and we'll have a pair of 'h's cancel like so

`(g(h+t)-g(t))/(h) = (5h^2+10ht+5h)/(h)\\\\(g(h+t)-g(t))/(h) = (h(5h+10t+5))/(h)\\\\(g(h+t)-g(t))/(h) = 5h+10t+5\\\\`

The left hand side cannot have h = 0, or else we have a division by zero error. But if we approached 0 (not actually getting there), then the expression 5h+10t+5 will approach 5(0)+10t+5 = 10t+5

---------------------

In short: The derivative of
`5t^2+5t` is
`10t+5`

In terms of symbols,
`g ' (t) = 10t+5`

Later on in calculus, you'll learn a shortcut so you won't have to compute the difference quotient every time you need a derivative. Refer to the power rule for more information.

After we find the derivative, it's as straight forward as plugging in t = 6 to compute g ' (6)

`g ' (t) = 10t+5\\\\g ' (6) = 10(6)+5\\\\g ' (6) = 60+5\\\\g ' (6) = 65\\\\`

Side note: This tells us that the slope of the tangent line is m = 65 when t = 6. In other words, this line is tangent to g(t) when t = 6, and this particular tangent line has slope m = 65.