Final answer:
To determine the temperature in Kelvin of 0.46 mol of gas at a pressure of 0.88 atm and a volume of 675 mL, we use the ideal gas law equation PV=nRT. After converting volume to liters and solving for T using the ideal gas constant 0.08206 L atm/mol K, we find the temperature in Kelvin.
Step-by-step explanation:
The student is asking for the temperature in Kelvin of a gas which we can find using the ideal gas law equation: PV=nRT. Here, P represents pressure, V is volume, n is the number of moles of the gas, R is the ideal gas constant, and T is the temperature in Kelvin we need to solve for.
Given that the pressure P is 0.88 atm and the volume V is 675 mL (which we need to convert to liters by dividing by 1000, thus V = 0.675 L), and the number of moles n is 0.46 mol, we can rearrange the ideal gas law equation to solve for T (Temperature in Kelvin).
Firstly, we use the ideal gas constant R with the units that correspond to the given pressure and volume units, which is 0.08206 L atm/mol K in this case. The equation to find the temperature T becomes:
T = (P x V) / (n x R)
Substituting in the provided values:
T = (0.88 atm x 0.675 L) / (0.46 mol x 0.08206 L atm/mol K)
After calculating, we can isolate T and provide the answer in Kelvin.