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A:HOW MANY DISTINCT ARRANGEMENTS CAN BE MADE WITH THE LETTERS IN THE WORD CONNECTION? B: HOW MANY AUTOMOBILE LICENSE PLATES CAN BE MADE IF EACH PLATE CONTAINS 3 DIFFERENT DIGITS…

A:HOW MANY DISTINCT ARRANGEMENTS CAN BE MADE WITH THE LETTERS IN THE WORD CONNECTION? B: HOW MANY AUTOMOBILE LICENSE PLATES CAN BE MADE IF EACH PLATE CONTAINS 3 DIFFERENT DIGITS…
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3 votes
A:HOW MANY DISTINCT ARRANGEMENTS CAN BE MADE WITH THE LETTERS IN THE

WORD CONNECTION?

B: HOW MANY AUTOMOBILE LICENSE PLATES CAN BE MADE IF EACH PLATE
CONTAINS 3 DIFFERENT DIGITS FOLLOWED BY 3 DIFFERENT LETTERS?

User Talon
by
7.6k points

1 Answer

4 votes

Answer:

A:The Reqd. No. of Permutations=3360

Explanation:

I couldn’t find the answer to B..sorry

User Jlstrecker
by
8.5k points
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