Question

A certain first order reaction has a half-life of 54. 3 s. How long will it take (in s) for the reactant concentration to decrease from 6. 50 m to 2. 27 m?

Answer 1

82.4 s

Step-by-step explanation:

Find the NUMBEr of half lives...then multiply by 54.3

2.27 = 6.5 (1/2)^n

log (2.27/6.5) / log (1/2) = n = 1.52 half lives

1.52 * 54.3 = 82.4 s