162k views
4 votes
If the temperature of a gas is increased from 20°C to 35°C, what is the new pressure if the original pressure was 1.2 atm? Assume that volume is constant.

Group of answer choices

A. 0.6 atm

B. 1.3 atm

C. 1.0 atm

D. 2.6 atm

1 Answer

2 votes

Answer:

B.) 1.3 atm

Step-by-step explanation:

To find the new pressure, you need to use Gay-Lussac's Law:

P₁ / T₁ = P₂ / T₂

In this equation, "P₁" and "T₁" represent the initial pressure and temperature. "P₂" and "T₂" represent the final pressure and temperature. After converting the temperatures from Celsius to Kelvin, you can plug the given values into the equation and simplify to find P₂.

P₁ = 1.2 atm P₂ = ? atm

T₁ = 20 °C + 273 = 293 K T₂ = 35 °C + 273 = 308 K

P₁ / T₁ = P₂ / T₂ <----- Gay-Lussac's Law

(1.2 atm) / (293 K) = P₂ / (308 K) <----- Insert values

0.0041 = P₂ / (308 K) <----- Simplify left side

1.3 = P₂ <----- Multiply both sides by 308

User Sophonias
by
6.8k points