Question

HELP ASAP THANKS

For the following questions, use the reaction NO2(g) - 1/2 N2(g) + O2(g), with ΔH = –33.1 kJ/mol and ΔS = 0.06302 kJ/(mol·K)

i. Draw a possible potential energy diagram of the reaction. Label the enthalpy of the reaction

ii. Is the reaction endothermic or exothermic? Explain your answer

iii. What is the Gibbs free energy of the reaction at 298 K

iv. Is the reaction spontaneous or nonspontaneous at 298 K? Explain your answer

please no fake answers I worked hard to get these points :/

Answer 1

Step-by-step explanation:

I. Kindly, see the attached image.

II. The reaction is exothermic.

III. - 51.88 kJ/mol.

IV. The reaction is spontaneous.

Step-by-step explanation:

I. Draw a possible potential energy diagram of the reaction. Label the enthalpy of the reaction.

Since the sign of ΔH is negative, the reaction is exothermic reaction.

In an exothermic reaction, the energy of the reactants is higher than that of the products.

Kindly see the attached image to show you the potential energy diagram of the reaction.

II. Is the reaction endothermic or exothermic? Explain your answer.

The reaction is exothermic reaction.

The sign of ΔH indicates wither the reaction is endothermic or exothermic one:

If the sign is positive, the reaction is endothermic.

If the sign is negative, the reaction is exothermic.

Herein, ΔH = - 33.1 kJ/mol, so the reaction is exothermic.

III. What is the Gibbs free energy of the reaction at 25°C?

∵ ΔG = ΔH - TΔS.

Where, ΔG is the Gibbs free energy change (J/mol).

ΔH is the enthalpy change (ΔH = - 33.1 kJ/mol).

T is the temperature (T = 25°C + 273 = 298 K).

ΔS is the entorpy change (ΔS = 63.02 J/mol.K = 0.06302 J/mol.K).

∴ ΔG = ΔH - TΔS = (- 33.1 kJ/mol) - (298 K)(0.06302 J/mol.K) = - 51.88 kJ/mol.

IV. Is the reaction spontaneous or nonspontaneous at 25°C?

The sign of ΔG indicates the spontaneity of the reaction:

If ΔG < 0, the reaction is spontaneous.

If ΔG = 0, the reaction is at equilibrium.

If ΔG > 0, the reaction is nonspontaneous.

Herein, ΔG = - 51.88 kJ/mol, so the reaction is spontaneous.