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You deal 7 cards off of a 52-card deck and line them up in a row. how many possible lineups are there in which no card is a club?

1 Answer

1 vote

Answer:

39C7 or 15380937

Explanation:

There are 13 clubs in a 52 card deck. We can remove these from the possibilities. 52-13=39. The rest is simple, choose 7 from 39 using the choose function is 39!/(32!*7!)=15380937. Or just say 39C7 as your answer.

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