Question

Simplify
`(6a^2 b^-^2)/(8a^-^3 b^3)` Assume a≠0 and b≠0

Answer 1

sorry i thought i knew it

Explanation:

Answer 2

3rd option

Explanation:

using the rules of exponents

`(a^(m) )/(a^(n) )` =
`a^((m-n))` : nm > n

`(a^(m) )/(a^(n) )` =
`(1)/(a^((n-m)) )` : n > m

`(6a^2b^(-2) )/(8a^(-3b^3) )` ← separate the variables

=
`(6)/(8)` ×
`(a^2)/(a^(-3) )` ×
`(b^(-2) )/(b^3)`

=
`(3)/(4)` ×
`a^(2-(-3))` ×
`(1)/(b^(3-(-2)) )`

=
`(3)/(4)` ×
`a^(2+3)` ×
`(1)/(b^(3+2) )`

=
`(3)/(4)` ×
`a^(5)` ×
`(1)/(b^(5) )`

=
`(3a^(5) )/(4b^(5) )`