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1 vote
Im pulling my hair out with this problem my calculator simplified it to
(1+/-√(14))/(10)

What am i doing wrong?? :')

Im pulling my hair out with this problem my calculator simplified it to (1+/-√(14))/(10) What-example-1
User S Pangborn
by
7.4k points

2 Answers

4 votes


~~~~~~~~~~~~\textit{quadratic formula} \\\\ 0=\stackrel{\stackrel{a}{\downarrow }}{3}x^2\stackrel{\stackrel{b}{\downarrow }}{+2}x\stackrel{\stackrel{c}{\downarrow }}{-5} \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ x= \cfrac{ - (2) \pm \sqrt { (2)^2 -4(3)(-5)}}{2(3)} \implies x = \cfrac{ -2 \pm \sqrt { 4 +60}}{ 6 } \\\\\\ x= \cfrac{ -2 \pm \sqrt { 64 }}{ 6 }\implies x=\cfrac{ -2 \pm 8}{ 6 }\implies x= \begin{cases} ~~ 1\\ -(5)/(3) \end{cases}

User Losttime
by
8.9k points
4 votes

Answer:

-5/3 and -1

Explanation:

I am not sure what you mistake is, but here is my solution. I hope that it helps. I am sorry that you are frustrated. We have all been there.

Im pulling my hair out with this problem my calculator simplified it to (1+/-√(14))/(10) What-example-1
User Jeffy Lazar
by
8.1k points

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